its really simple
R1+R2 = 16
R1R2R1+R2 = 3
solve these two equations , ull get one resistance as 12Ω and the other as 4Ω
when two resistors of resistance R1 and R2 are connected in parallel,the net resistance is 3ohm.When connected in series,it's value is 16ohm. calculate the values of R1 and R2.
its really simple
R1+R2 = 16
R1R2R1+R2 = 3
solve these two equations , ull get one resistance as 12Ω and the other as 4Ω