Parallel Plate Capacitor

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The space between the plates of a parallel plate capacitor is filled consecutively with 2 dielectrics 1 and 2 having thicknesses d₁ and d ₂ and permittivities as Îµ₁ and Îµ₂ respectively . The area of each plate is S . Find the density of the bound charges on the boundary plane if the voltage across the capacitor is V and the electric field is directed from dielectric 1 to dielectric 2.

#Physics #Electricity and magnetism

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iitimcomin ·2009-06-20 23:19:44

soo we just have to find capacitance .... a simple logic is used here which is potrayed below...

C = eA/d ........ now if i introduce a med. of rel. permittivity k ...... C = ekA/(d) = eA/(d/k) ..

or it is equivalent to a distance of d/k in vaccume !!!!!!!!!!!!!!! therefore we have ur net distance in vacc . to be d1/e1 + d2/e2 ,,,,,,,,,,,,

C = eA/(d1/e1+d2/e2) ...................now the chare on the cap = CV .........

SO CHARGE = eAV/(d1/e1+d2/e2)

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Parallel Plate Capacitor

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