The space between the plates of a parallel plate capacitor is filled consecutively with 2 dielectrics 1 and 2 having thicknesses d1 and d 2 and permittivities as ε1 and ε2 respectively . The area of each plate is S . Find the density of the bound charges on the boundary plane if the voltage across the capacitor is V and the electric field is directed from dielectric 1 to dielectric 2.
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1 Answers
3soo we just have to find capacitance .... a simple logic is used here which is potrayed below...
C = eA/d ........ now if i introduce a med. of rel. permittivity k ...... C = ekA/(d) = eA/(d/k) ..
or it is equivalent to a distance of d/k in vaccume !!!!!!!!!!!!!!! therefore we have ur net distance in vacc . to be d1/e1 + d2/e2 ,,,,,,,,,,,,
C = eA/(d1/e1+d2/e2) ...................now the chare on the cap = CV .........
SO CHARGE = eAV/(d1/e1+d2/e2)
