1133Ans. 3e
E = V/d
Then, qV/d = mg
Solve for q.
Two metal pieces having a potential difference of 800 V are 0.02 m apart horizontally. A particle of mass 1.96 X 10-15 kg is suspended in equilibrium between the plates. If e is the elementary charge, then charge on the particle is
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2 Answers
21V=ED; E=V/D
F=QE; E=F/Q
F/Q=V/D ;
mg/Q=V/D; .......(1)
so, Q= mg*D / v
= 1.96*10^-15 * 0.02 / 800
= 4.802*10^-19
Charge on the particle = 4.802*10^-19 / 1.6*10^-19
=3
Q =3e (Ans)
