1@madhumitha supossedly i m not tlking but just posting a reply!
when connected in series it will be a equivalent capacitor with charge 3C and equivalent capacitor of C/2
therefore V=6V[1]
u made a blunder in ur solution
two identical parallel plate capacitors are connected in parallel to a 3V battery.the battery is disconnected and the two capacitors are joined in series.what is potentiasl diference across combination?
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7 Answers
1hmm.mera purana dbt hai ye mera answer 6V ayya tha..book wrote 12V .......lets wait for others!
1ok so this is how i did it.
when capac. are connected to battery, current will flow until volatge at all points is 3V. so voltage across 2 parallel capacitors has to be 3V.
now, V=Q/C, since they are in parallel, it will be, 3=Q/2C, so Q=6C
now, connect them in series.
V=Q/C = Q/C/2 = 2(Q/C)=2(6C/C) = 12
11umm yeah ur right. my bad. idk then, answer shuold be 6