29Abt the principle of superposition....it is helpful in finding the net resistance of some complicated circuits which have axis of symmetry..just fold the circuit abt that axis and the two symmetric resistances will be in parallel....
Can anyone plzz explain the principal of superposition in electrical circuits
I have learnt it before from Arihant
But had some conceptual doubts
Hence this thread
-
UP 0 DOWN 0 0 6
6 Answers
29
62It simply says that the voltage soruces act as if the others were not present.
So you can solve the circuit neglecting the other emf sources and finally adding the individual effect of all the emf sources individually..
4
CAN U SOLVE THIS BASED ON THE PRINCIPLE PLZZ????
RESISTORS LOOK MORE LIKE WORMS DONT MIND [3]
11Yes - first consider the circuit with the 10.3V battery, and the other one is absent. Figure out the current in the individual branches.
Now repeat the same thing with the other battery, finally add up the individual currents in each branch.
Could not provide numerical soln, due to respect for some fantastic art-work. [26]
62Firstt look at the 10.8 V battery only
Lets say that we are interestedin the current through the 12 ohm resistor..
So we will remove the 14.4 V
SO we have a parallel between 12 and 8 whcih will effectively be 12.8/(12+8) = 96/20 = 4.8 ohm..
That along with 4+2+4.8=10.8 ohm
THe current due to this is 10.8/10.8=1 in the main wire and 8/20 ampere in the wire through the 12 ohm resisitor
Again repeat the same for 14.4 (we remove the 10.8 ohm resistor)
We have (4+2) and 12 in parallel.. effective reisistance = 12x6/18 = 4 ohm
In series with another 8 which is 12 ohm..
14.4/12=1.2 of which, (4+2)/18 x 1.2 = 0.4 amp goes in the 12 ohm resistance
Also the direction of current is opposite due to both .. so the net current will be 1-.4=.6 amp.
4ThaNks Nishant Sir , Soumik & Govind
@Nishant Sir thanks for the solution of the prob
I've got a clear idea now [1]