Rini = Ïl/A
Rfinal = Ï(1.1l)/(A/1.1) = (1.21)Rini
% change = 21%
A wire is stretched to increase it's length by 10%.Find the percentage change in it's resistance..............................plz solve this sum for me.
Rini = Ïl/A
Rfinal = Ï(1.1l)/(A/1.1) = (1.21)Rini
% change = 21%