rather easy but still help !

46 Answers

1
Pavithra Ramamoorthy ·

let l be 2pir....

1
Pavithra Ramamoorthy ·

hey got it..

d potentials must be same...

1
Pavithra Ramamoorthy ·

let e1=B2pir(2v)=4B(pi)rv

e2=B2(pi)(2r)(V)=4B(pi)rv

11
Subash ·

no answer is 8rvB

help please

11
rkrish ·

are the rings rolling or sliding on the surface??

11
Subash ·

Two conducting rings of radii r and 2r move in opposite directions with velocities 2v and v resp. on a conducting surface S. There is a uniform magnetic field of magnitude B perpendicular to the rings. The potential difference between the highest points of the two rings is ?

(options available on request)

please solve this from the basics and fully so that i can get the concept clearly !

1
Pavithra Ramamoorthy ·

@krish ...... i don think dis makes a diff..........

11
Subash ·

guys help with this one

1
prateek punj ·

hey yar perpendicular kis ke...axis ya phir plane of rings.....

11
Subash ·

plane of the rings

11
Subash ·

bhaiya help here too

1
skygirl ·

ans?? 8vrB?

1
skygirl ·

ans?? 8vrB?

1
Pavithra Ramamoorthy ·

he posted d ans already..................

solve it here............

11
Subash ·

yes sky answer correct explain too!

1
skygirl ·

o sorry. i din c.... will solve ..

coming from dinner.....

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