resistance of shunt

The resistance of the shunt required to make the range n times for an ammeter of ressistance R is

(a) nR

(b) (n â€“1)R

c) R/(n â€“1)

(d) R/n

6 Answers

Lets look at it like this..

a) We want 1/10th current to flow thru the ammeter.

B) we connect the shunt in "parallel" or series?

see assume the minimum c urrent to be = I
But we want nI to be measured
Therefore
(n-1)I would be bypassed
Therefore
IR = (n-1)I * r
r = R/n-1

There fore option c

parallel therefore the voltage is same
Reason for IR = (n-1)I * r

Shivani pls check out
Any problems?

nopes,thnx for the solution

pink pls

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