ring...

2 Answers

ans. (4)

dE sinÎ¸ component of both halves cancel.

So E = âˆ«dEcosÎ¸

where dE = kdq/r²

taking limits from 0 - Î /2,

we get E = q/2Î ²Îµ₀r² along -ve y-dirn

hey one typing error... that should be

E = âˆ« 2 dEcosÎ¸ if limits are taken from 0 to Î /2
or
E = âˆ« dEcosÎ¸ if limits taken from -Î /2 to Î /2

however the answer given in the above post is correct.

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