Someone plz....solve this :-(JEE Advanced 2013)

VITEEE 2015 Guidance › Electricity and magnetism questions › Someone plz....solve this :-(JEE Advanced 2013)

Q) One end of a horizontal thick wire of length 2L and radius 2R is welded to an end of another horizontal thin copper wire of length L and radius R.When the arrangement is stretched by applying forces at two ends, the ratio of the elongation in the thin wire to that in the thick wire is ? (JEE Advanced 2013)

#Physics #Electricity and magnetism #Electric Current

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Aditya Agarwal ·2014-04-27 06:37:19

Y=F.2LÏ€.4R².Î”L₁

â†’ Î”L₁=2FL4Ï€R²Y
Again for 2nd wire,
Y=F.LÏ€R².Î”L₂

â†’Î”L₂=FLÏ€R²Y

Î”L₂Î”L₁=2

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Anirudh Prasad (Anidaniel) Thnx ....!!! it is the ri8 ans..!!! :D
Upvote·0· Reply ·2014-04-29 00:27:35
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