Solution :
current in R4 and R3 is (6-5)/5=1/5A
VCD=VCA=VCB (no current is flowing through R1)
V=VCB=E2+iR2=2 + 2/5=12/5A
E=(1/2)CV2
21OH KK.....
THANX YAAR......... thanx a ton!!!
BTW ek doubt tha.......
Y didnt u make use of R3 in ur calculation?
Was it bcoz it didnt fall in the LOOP that u had selected?
Does that mean No matter wat be the value of R3 our answer does not change?? [7]
1bahut bekar bane hain i know agar kuch samajh na aaye to puch leena
21OKIE!!!!!!11
ab Step 1 percfectly CLEAR!!!!!
thnq firse DUDE
[1]
1nahi step 1 main R3 use hoga find net current 5 and 4 ohms in parallel so net resistance 20/9 hoga net i=27/10 current in req branch dat is 2 ohm and 3 ohm wala branch will be 6/5 A
21thn how did u get 6/5A buddy,
coz E = E1 = 6V;
Thn how did u gt R =5??
1in step 1 we will certainly use R3 but in next 2 steps u replace R1 by a wire with 0 resistance so whole of current will pass through it and R3 will be useless thats why i didnt use it in step 2 and 3
[4][4][4][4]
39answer nahiin match hora kya? tera method toh sahiin hain. use the fact that it offers infinite resistance in steady state
1k we use superposition principle
another thing we hav to find V btw E2 and end of R2
ie ---------||-----------/\/\/\/\----------- ----------------> (arrow shows the direction of current)
||=E2 /\//\/\/\=R2
now step 1:
replace E2 and E3 by wires and find the current in above part of circuit shown with only E1
we will get a current 6/5 A parallel to the given directional arrow ( which i showed above)
step 2
similarly replace E1 and E2 and calculate current in req part of circuit
it comes out to be 2/5 A opposite to the arrow i showed
similarly step 3
using only E3 we get 3/5 A in opp dir to ma arrow
so net current in our required part of circuit is 1/5A parallel to ma arrow
now find the required potential drop V=12/5 V
so energy = 5*12*12/2*5*5=144/10=14.4 units
[4][4][4]
21YAH VISH
u r crrct bro! ans givn is C
Can u pl. post ur workin in a lil mor detailed way
1i did it by superposition and of coure R3 has to be considered for it
21lagta aisa hi he.... the symbol is lil wierd but I m not sure if its ohm or sumthing else..... par in da diag resistor only has bn shon
21pl. try this yaaron...........
Its quite simple, u jus need to assert or oppose the solution provided........
MY MAIN DBT. IS : Y DONT V CONSIDER R3 wile calculatin resistance?
21NO.
ACTUALLY, my methd dusnt match wid da abov mentioned methd..............
its a que frm Tiit FT1
but y do v not consider R3?????????????/
