tell me the direction..

the current density across a cylindrical conductorof radius R varies ; j=j0 {1-r/R} ,where r is the distance frm the axis .thus the current density is maximum j0 at the axis r=0 and decreases linearly to zero at surface r=R calculate current in terms ot joand surface area of conductor is A= pi R2

4 Answers

66
kaymant ·

Use the fact that the current is the flux of the current density vector to obtain
i=\int_0^R j_0\left(1-\dfrac{r}{R}\right)2\pi r \ \mathrm{d}r

1
parnika -1 ·

so here current flows radially outward....!!!

66
kaymant ·

no..it flows parallel to the axis

1
parnika -1 ·

sir can u xplain wid digram......im still confused..!

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