Use the fact that the current is the flux of the current density vector to obtain
i=\int_0^R j_0\left(1-\dfrac{r}{R}\right)2\pi r \ \mathrm{d}r
the current density across a cylindrical conductorof radius R varies ; j=j0 {1-r/R} ,where r is the distance frm the axis .thus the current density is maximum j0 at the axis r=0 and decreases linearly to zero at surface r=R calculate current in terms ot joand surface area of conductor is A= pi R2
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4 Answers
kaymant
·2009-07-07 05:54:57