1no celestine that is the method .
actually without lamis theorem and cnonsidering tension one may make it bulky...
your solution is elegant ...
this wasnt intended to be a special problem just a simple one from my side. ...:)
A charged particle (mass m) is hanging from a point and is just abocve the ground initially.
Let the position of the charged particle now be G ..
A man brings another charged particle from infinity to G along a straight line and observes that finally the charged particle rises to a height H as shown in figure .
Find the work done by the man..
This problem is easy but It could be done in a very elegant manner ..
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18 Answers
1nothing else is given in problem ! they can be unequal to
take everything general except the quantities mentioned
1
9yes i ve applied lamis thm only rohan
kaymant sir too thinks u have another elegant method post it pls
1as forces are equaling to zero .. we have them making a triangle
so just apply law of similarity of traingles...
66Rohan, what Celestine did was the usual way one would have proceeded. What "elegance" [1]did you find in it? (do not take it otherwise Celestine). And do post your "elegant" method.
9it wud be interesting to see ur method pls post it rohan i might learn something new
1yes this was the reqd elegance (my method is slightly different .. does not matter)
9rohan why are u using 2 ids ?????
moreover the name satan doesnt sound good [3]
1ONLY 12 views !!!!
cmon guys this is not a bad problem ... atleast read it !
1the concept is right .. but its implementation is vital
that is what i need!
11Also the equilibirium position of the first charge has to be found with FBDs
11Is it like this
Initial energy =0
Final energy= Grav PE+ Elect PE
This energy comes from the work by the man
1G is not mentioned in figure ..
it is the initial position of the hanging charged ball