SRMEEE - A COMEDY OF ERRORS??

oh i am so sorry anirudh! s stupid of me! .. i shudn't have just left it like dat ....

but may be i saw u in some discussions of C++ in the forum [i may be utterly wrong.. jus' pardon me for that re] so thot u are a CS student..

anyways now thats ur dbt is over... its gr88 !!

cheers ! ~

As given in definition

a_ij=-a_ji for all i,j (not for i≠j alone)

so for i=j

a_ii=-a_ii(so it is zero)

Got it?

Have mercy, sky. I'm a bio student.

How can both conditions be the same?

a_ij = − a_ji

is for i≠j. Nothing is said about the diagonal elements. Understood my doubt?

It's given or...so either of the conditions have to be satisfied right?

In linear algebra, a skew-symmetric (or antisymmetric) matrix is a square matrix A whose transpose is also its negative; that is, it satisfies the equation:

A^T=− A

or in component form, if A = (a_ij) :

a_ij = − a_ji for all i and j.

wiki defenition........ shd both conditions be satisfied?

sky, is it necessary that the diagonals elements shd be 0?

I don't think so .... cos any matrix such that a_ij=a_ji for i≠j

The diagonal elements don't matter, right?

*************edit**********

a_ij=-a_ji

wat is skew symmetric???????????

wat about the first one?

2) they forgot to give NO2 or something else like CH3 etc [they only know wat !] in both 1 and 3.

so may be first one will be ortho! as NH2 is placed in such a position as if there is something.........

leave it !

Ankit,

sin(π+θ) = -sinθ

cos(θ-π) = cos(π-θ) = -cosθ

tan(π-θ) = -tanθ

So the matrix becomes,

\begin{bmatrix} 2sin\theta -1 & sin\theta &cos\theta \\ -sin\theta & 2cos\theta -\sqrt{3} &tan\theta \\ -cos\theta & -tan\theta & 0 \end{bmatrix}

In the above matrix u can clearly see that a_ij=-a_ji for all i≠j (which is how a skew-symmetric matrix is defined)

So how does the value of θ matter???

2nd ans is c ...... but the question is Comedy ! :)

the ans for 1st is π/6 ... since the elements of leading dioganal is 0 at π/6

i think u will get it for pi/6