11can some one explain this
If a is a natural number and b a digit such that (3a+2007)2=4b85924' then a+b=
a.31 b. 35 c.37 d. 41
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5 Answers
1357left side is multiple of '9'
so sum of the digits on RHS should be multiple of 9
b+32=9n
this might help
62taking forward manish's arguement..
b+32=9n
b is less than 10
so 36 is the only possibleiyt ie b=4 and n=4
√4485924=2118
hence 3a+2007=2118
3a=111
a=37
and thus, a+b=41
