AMTI october 2008

Abhishek which of these could you not solve?

I did not comment on the no of questions.. bcos i am myself not very sure... the questiosn are good no doubt :)

may be we can skip geometry

hey 6 is simple

find f(0,0) .. and then proceed..

Not as tough as u may think!

put x=y=z
f(x,x) =1

put y=z
f(x,y)f(y,y)f(z,x)=1
f(x,y)f(y,x)=1

f(x+2,x+1)f(x+1,x)f(x,x+2)=1
2.2.f(x,x+2)=1
f(x,x+2)=1/4
f(x+2,x)=4
f(0+2,0)=4

following thus, we get f(m,n)=2^m-n

a couple of induction steps remain in between .. that i have left for u to figure out :)

gr8.. congrats :)

oh btw does that smell like some cheating?