3actually it is a formula that can be derived by the elementary operation becos tanA=sinA/cosA for A=pi/2 it is infinity.we dont know infinity so how can u perform calcuations.
tan(A+B)=sin(A+B)/cos(A+B)
Q
We know that tan(A+B)=tanA+tanB/1-tanAtanB
now we waana find the value of tan ∩.
A child puts both A and B as ∩/2
But now he is trapped a tan ∩/2 is not defined.
He solved the question by the use of L Hospital
But he wonders what is the BASIC way to do it rather than using expansions or else?
Please help him out.
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10 Answers
11arrey subash bhai
we can use L hospital as it is ∞/∞form?
iss it correct?
3
11haan cele bhai
its exactly what u r saying
but the question is
WHAT IS THE PROCEDURE TO FIND THE LIMIT?
11bhai woh to aata hai
its done by that way
i am asking 4 a BASIC method[1]
11@ manipal
tan ∩ = 2tan∩/2/1-tan2∩/2
tan ∩/2 = x
tan ∩ = 2x/1-x2
Now take x down
tan ∩ = 2/1/x - x
1/x = 0
-x = -∞
And therefore 2/∞ = 0
tan ∩ = 0