CONFUSION.........

BITSAT 2015 Preparation › Fundamentals questions › CONFUSION.........

If i take y=x^{x^x}.......and
use log.......
CASE 1.. logy=x^xlogx...
CASE 2....logy=xlogx^x
=logy=x²logx...........WHICH IS CORRECT??

#Mathematics #Fundamentals

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6 Answers

1

Akand ·2009-03-15 22:38:24

koi bolo naa plzzzzzzzzzzzz

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62

Lokesh Verma ·2009-03-15 22:42:02

These are 2 differnt things

\left(x^{y} \right)^{z}

and

x^{(y^{z})}

now you have to say!

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106

Asish Mahapatra ·2009-03-15 22:43:33

ya bhaiyya ... case (i) is correct .. actually x^{x^{x^x}} = x^{(x^{x^x})}

so. case (i) is correct

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1

Akand ·2009-03-15 22:44:10

yup...................got d answer for my illogical foolish dobt

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1

Akand ·2009-03-15 22:45:54

so can I say x=2??? hehehe

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62

Lokesh Verma ·2009-03-15 22:46:36

Yes asish..

i agree to you.. but still this is an ambiguity that must be made clear by the question setter.

I am not very sure/aware if there is a "standard" (Internationally accepted) convention for this one...

But i wud go with what you have just written.

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Your Answer

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