1
Akand
·2009-03-16 09:26:15
hehe ok manipal............u deserved it
1
dimensions (dimentime)
·2009-03-17 08:36:13
ok i have a more simpler proof given \small |\beta |=1\\ so,\beta =\frac{1}{\bar{\beta }}\\ let\ Z=\frac{\beta -\alpha }{1-\bar{\alpha }\beta } \\ or, Z=\frac{1-\alpha \bar{\beta }}{\bar{\beta }-\bar{\alpha }}\\ taking\ bar\ on\ both\ side,\\ \bar{Z}=\frac{\beta -\alpha }{1-\bar{\alpha }\beta } \\ so\ from\ both\ equation\ we\ have, Z\bar{Z}=1\\ or\\ |Z|=\left| \frac{\beta -\alpha }{1-\bar{\alpha }\beta }\right|=1 & it is not necessary that |@|=1 !!!
21
tapanmast Vora
·2009-03-16 10:15:21
website mili but how to insert that ROTFloor smiley here?
11
Mani Pal Singh
·2009-03-16 09:57:43
YEH LE
http://www.artofproblemsolving.com/Forum/images/smiles/rotfl.gif
3
iitimcomin
·2009-03-16 09:54:59
philip kahan se woh smiley mila????????????
11
Mani Pal Singh
·2009-03-16 09:52:27
@ AKAND
FROM NOW DONT ASK 4 PINKS
PINK UR ANSWER BY UR OWN
IF U THINK IT DESERVES!!!!!!!!!!!!!!!!!!
1
Akand
·2009-03-16 09:34:40
waaaaaaaaahhhhhh bhaiyya......u dint giv pink waaaaaaaahhhhhhh
11
Mani Pal Singh
·2009-03-16 09:23:51
NO ONE GIVES ME PINK [17][2]
I DECIDED TO HAVE MIN[1][3][4]

1
Akand
·2009-03-16 09:20:59
bhaiyya no pink over here????
1
Akand
·2009-03-14 10:15:42
yup and |α| has to be 1.........
1
Akand
·2009-03-14 10:14:02
TAKE ZZ=|Z|2...wher Z is d given expression..........
so......
.(β-α)(β-α)/(1-αβ)(1-αβ)
=
(β-α)(1-α)/(1-αβ)(1-α)
=
(β-αβ-α-αα)/(1-α-αβ-αβα)
do more simplification and ull get 1....
1
Anuj
·2009-03-14 10:12:20
nothing given about mod a, sri shankara charya...
1
Anuj
·2009-03-14 10:11:17
ncert book is also visible in 2nd pic.............further, do u remember the Q only or ans too???????[7]
1
Akand
·2009-03-14 10:07:29
hey this is a CBSE question naa???? i remember it.
1
MATRIX
·2009-03-14 10:02:41
is der ny relation given between β and α anuj.......