1i think zero..............i bet this is a selfmade question......
11no
a very gud ques
try if u can or i will post the answer
1
Akand
·2009-03-06 07:16:07
ok............
sin(x+iy)
-1≤x+iy≤1
since u cant do this for imaginary......so y=0
-1≤x≤1
so same as normal sinx.........
1
Akand
·2009-03-06 07:16:37
wel toughest ive heard is tht cauchy wala
11how can a complex number be thin :O
11
Subash
·2009-03-06 07:18:57
hey akand i think u did for sin-1
chek ur limits
11
Mani Pal Singh
·2009-03-06 07:19:43
yeh itna mushkil nahin hai jitna tum isse bana rahe ho
11
Subash
·2009-03-06 07:21:34
u are still not saying what it is =
is it y=sin(x+iy)
1
Akand
·2009-03-06 07:25:08
wel for y=sin(x+iy)
y=sin(x)cosh(y)+i.cos(x)sinh(y)...... and then dont kno
1
Akand
·2009-03-06 07:41:09
but dude..............we dont have hyperbolics naa????
1
Akand
·2009-03-06 07:49:38
sinh and cosh are hyperbolic functions which are not in d syllabus......
