hilarious doubts of ATGS...

BITSAT Preparation › Fundamentals questions › hilarious doubts of ATGS...

x²+y²=1....is a circle..
so, y²=1-x²...is a circle..
implies.., y=Â±√1-x²...

so what is the graph of y=Â±√1-x²(sin x)

please help...also point out wether or not the doubt makes any sense...

#Mathematics #Fundamentals

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7 Answers

49

Subhomoy Bakshi ·2010-01-29 10:41:19

arre koi toh answer karo!!

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1

Che ·2010-01-29 21:11:29

actually wat i think is pattern of the graph will be quiet similar to graph of x. sin x for y=+âˆš1-x²sinx and -x. sin x for y=-âˆš1-x² sinx

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49

Subhomoy Bakshi ·2010-01-29 23:13:25

yup...then explain y x²+y²=1 is a circle??

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Che ·2010-01-29 23:19:08

wat!?

wer r u contradicting that x²+y²=1 is not a circle!

din get ur point

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49

Subhomoy Bakshi ·2010-01-30 00:26:51

x²+y²=1
implies, y=Â±√1-x²

whch r two st lines...

so y is the function a circle???

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1

Che ·2010-01-30 00:32:47

array how r dey two str lines ??

infact y=âˆš(1-x²) is equation of semi circle

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archana anand ·2010-02-04 09:22:32

@ subhomoy i dont think x²+y²=1 represent a function itz a relation.....so y=√1-x² is not a function of st line at all

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