Inverse

dei, i have posted the complete question.....idhu dhan irundhudhu..

assuming it is bijective function ........

sorry a small error ...... make it .........

log√x+1/1-x = y ............

clearly its definded only for x ε [1,0) U (0 , - 1)

take componento dividento on both sides

we get

1+y/1-y = 10^2x

take log

and we get x = log√y+1/1-y

replace x by y ,,,

hmmm......brilliant da

thank u very much!!

epidi irindidu ... entrance exams ellam ...?????

bore da..... slept at almost all exams.....sunday after sunday. What do u expect me to do?

nala panalaya?????????????????????

did well (except in JEE).....but really boring

i thought this period wud be really exciting

was a sitter mates