MATH EXPERTS KE LIYE HI........

PL NOTE : I KNOW how to solve the following Question ...............

My concern is the type :

IN such Questions wat is the instinctive Substituition one MAKES or waat are the primary OBSERVATIONS/DEDUCTIONS/SUBSTITUITIONs one shud at once think of after reading this type wer f(x) = f(x+n)*blah blah ....

PL. inform wat techniQ shall be the Quickest!!!

19 Answers

21
tapanmast Vora ·

Sir, NOT for this eg. I m toking of IN-GENWERAL ........ wats da shortest?? or is it Case To CAse BASIS only??

lyk wat shud u hunt 4 at first sight in this type........

1
archana anand ·

ok thanx

62
Lokesh Verma ·

include it..

but what i meant by remove is that from the 2nd part...

1
archana anand ·

r v suppose to remove the last case i.e.the terms where there is only 1 of them being used that is 3C1x 110 or include it???

21
tapanmast Vora ·

oh ya quite definitely not.......

but lyk ne typical cases / eye-catcehrs that v must luk 4 wen v c dis ......

341
Hari Shankar ·

there is no 'one size fits all' answer for this.

You have to play around and be alert for the possibilities at every stage.

21
tapanmast Vora ·

SIR, pl reply to this :

IN such Questions wat is the instinctive Substituition one MAKES or waat are the primary OBSERVATIONS/DEDUCTIONS/SUBSTITUITIONs one shud at once think of after reading this type wer f(x) = f(x+n)*blah blah ....

62
Lokesh Verma ·

a dice is rolled 10 times.fined the no of ways in wich the outcome contain 1,2,3
ans: (310)-(3c2*210)+(3c1*110)

the expression above is a case of inclusion exclusion principle..

you first pick the numbers from 1,2,3 with any number of repetitions
that is 310
then we remove the terms where there are only 2 of them being used.. that is (3C2210)

Now we remove those with only 1 number that is 3C1x 110

1
archana anand ·

a dice is rolled 10 times.fined the no of ways in wich the outcome contain 1,2,3
ans: (310)-(3c2*210)+(3c1*110)

11
rkrish ·

g(x)=logf(x)
g(x+1)=logf(x+1)
g(x+1)-g(x)=log[f(x+1)/f(x)]=logx
g''(x+1)-g''(x)=-1/x2

The above is frm Manish bhaiyya's post #9

Now put N=1 & x=1/2
You get
g''(1/2 + 1) - g''(1/2) = - 4
Putting N=1 in the options , only A satisfies

This is short indeed. [1][1]

1
skygirl ·

do u want subjective type solution or objective type ?

21
tapanmast Vora ·

Sir, u shayad missd out on my FIRST line...........
This is wat i wanna know.....

IN such Questions wat is the instinctive Substituition one MAKES or waat are the primary OBSERVATIONS/DEDUCTIONS/SUBSTITUITIONs one shud at once think of after reading this type wer f(x) = f(x+n)*blah blah ....

PL. inform wat techniQ shall be the Quickest!!!

P.N. the eg. attested is jus an example of the type............ I managed to solv the eg.

I wanted sum tips 4 generalization on Such topics ,,,,,,,,,,,,,

1357
Manish Shankar ·

g(x)=logf(x)

g(x+1)=logf(x+1)

g(x+1)-g(x)=log[f(x+1)/f(x)]=logx

g''(x+1)-g''(x)=-1/x2

putting x=1/2, 3/2 ...., (2N-1)/2

g''(3/2)-g''(1/2)=-1/(1/2)2
g''(5/2)-g''(3/2)=-1/(3/2)2
.....................
g''(N+1/2)-g''(N-1/2)=-1/((2N-1)/2)2

adding it you will get the result

I don't have any other method (shorter)

21
tapanmast Vora ·

SIRsssss pl. help

1
skygirl ·

but you need g'(x) not f'(x)... it will be same i think..

11
Mani Pal Singh ·

why not we use
f(x)=eg(x)
then differentiate

things become a hell lot of simpler !!!!!!!!!

1
skygirl ·

[3] ok for abhi....

take f(x)=(x-1)f(x-1)

so, g(x)= ln(x-1) + ln(f(x-1))

now diff two times..

then try to find out the term for N=1 :P

then substitute Nin the ans and see which one satisfies :)

21
tapanmast Vora ·

SKY : Solution aata hai mere ko...........

13
Двҥїяuρ now in medical c ·

i want objective type[3]

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