Let (h,k) be new centre.
(h-2)2 + (k-4)2 = 4
only A & D satisfy this condition.
Radius of only A = 2 = radius of original circle.
this is a new thread in which all types of maths sums can be posted,
rules: 1) only 1 question at a time
2) no one start a new question unless the previous one is fully solved by someone and understood by everyone
3) every question must have options and must be of jee level.
4) this thread is only for seniors as they are the ones whu have covered the whole syllabus
5) question must be objective , solution must not be too long , but the question must be tricky( I HOPE EVERY ONE HAS SEEN JEE SOLUTIONS)
so guys i will start with a gud question:(easy one, but gud for start]
1)THE CIRCLE X2+Y2-4X-8Y+16=0 rolls up the tangent to it at (2+√3 , 3) by 2 units , assuming the x axis as horizontal , find the equation of the circle in the new position-
a)x2+y2-6x-2(4+√3)y+24+8√3
b)x2+y2-6x-2(2+√3)y+24+8√3
c)x2+y2-6x-2(4+√2)y+24+8√3
d)x2+y2-6x-2(4+√3)y+24+4√3
Let (h,k) be new centre.
(h-2)2 + (k-4)2 = 4
only A & D satisfy this condition.
Radius of only A = 2 = radius of original circle.