n-sided polygon

Find the maximum number of sides of a n-sided polygon, the sum of all the angles of which is less than 2011° and hence find the sum of all the interior angles of the polygon.

4 Answers

1
kunl ·

some guys seem a big fan of IMO (this was for number "2011" :P)

1
ninepointcircle ·

is the polygon regular?

36
rahul ·

nopes the polygon is not at all regular. Its dead easy. Just a lill formula work and Inequality kills the question.... :P

36
rahul ·

I think i gotta post the solution..

The sum of all the angles of a n-sided polygon is given by 180° x (n - 2)

So, A To Q,

180° x (n - 2) ≤ 2011°

=> (n - 2) ≤ 11.17222....

but since, (n - 2) is a positive integer so,

(n - 2) = 11 [as we need to find the maximum number of sides]

=> n = 13

Thus, sum of all the interior angles = 180° x 11 = 1980° Ans...

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