ok......practice for CBSE math.....easy stuff

THIS IS SERIOUSLY NOT FOR IITJEE practice.....THEY ARE 2222222 EASY............ ONLY FOR CBSE sure shot QUESTIONS...

Please other guys dont scold me for these easy questions..
1. Find the principal value of tan-1(tan7∩/6)+cot-1cot7∩/6.....

2.Evaluate...o∫∩/2(x+sinx)dx/(1+cosx)...

3.Two tailors A and B earn Rs.150 and Rs. 200 per day respectively. A can stich 6 shirts and 4 pants per day whike B can stich 10 shirts and 4 pants per day. How many days shall each work if it desired to produce atleast 60 shirts and 32 pants at a minimum labour cost?? GRAPHICALLY..........

Solve these yaar u cud be sure of 11 marks in d next board paper..

61 Answers

11
Mani Pal Singh ·

TRIGONOMETRY +2 KE BOARDS MEIN NAHIN HAI[3]

11
Subash ·

hey KR 2 is wrong i think limits are not -a to +a sort

1
Akand ·

u gotta be kiddin sky..........thts wat they teach u at d startin of d year....d principle intervals of inverse functions......
wel i guess u do complex and difficult questions only hehehe...[3][3]
k...take d interval for tan inverse and ull get in a second....its a ONE mark question........

try 2nd its nice...may take a while

1
Anuj ·

tryin' the 3rd.........

what to do in 1st and 2nd

1
Akand ·

wat do u mean wat to do??????
INTEGRATE in 2nd.............................and find d final value in 1st......

11
Mani Pal Singh ·

1)principal value of tanx varies from-∩/2 to ∩/2
so ∩/6+∩/6=∩/3

1
Anuj ·

3. Rs 1350
a works for 5 days, B works for 3 days

11
Mani Pal Singh ·

2)HINT its an ODD function[1]

1
Anuj ·

i mean how to integrate???

and how to proceed in 1st????

1
Anuj ·

3rd correct???[7][7]

i hope it is.........

1
Akand ·

hey mue................check tht 3rd again.....u r gettin an unbounded region rite?????? so did u try for 150x+200y<1350??? thts d tricky part..............u havent finishd d question yet..

1
KR ·

1)=tan^{-1}\left(tan\left(\frac{7\pi }{6} \right) \right)+cot^{-1}\left(cot\left(\frac{7\pi }{6} \right) \right) \Rightarrow tan^{-1}\left(tan\left(\pi +\frac{\pi }{6} \right) \right)+cot^{-1}\left(cot\left(\pi +\frac{\pi }{6} \right) \right)\Rightarrow tan^{-1}(tan(\frac{\pi }{6}))+cot^{-1}(cot(\frac{\pi }{6}))\Rightarrow \frac{\pi }{3}6)

1
Anuj ·

i dont know what to do of graph...[2][2][2]

1
KR ·

let f(x)=o∫∩/2(x+sinx)dx/(1+cosx)...

i think we can get after splitting it........
and putting cosx =t;{thinking.........}

11
Mani Pal Singh ·

@KR do read post 6&8

1
KR ·

[17] [17] sorry MS , i was RENDERING EQUATION using that LATEX , it really took a lot of time..[17][17]

1
skygirl ·

yeh pehla wala mereko koi batado kaise karte hai ....

1
Akand ·

yup........................i told its tricky

11
Subash ·

seprating it into two integrals would be the trick i think

1
KR ·

[17][17]

11
Mani Pal Singh ·

good catch subash
at least arent fooled by my ststement
it was just a fact and not a way to approach a problem

1
Akand ·

wel subash there is an easier trick..........think cbse ques??

1
prateek punj ·

hey akand r these just the ques by u or hav any resource that u r writting them to be coming in brds...

11
Subash ·

well then

0∫af(x)=0∫af(a-x)

1
Akand ·

try tht............i tried to.........u wont get it.......

11
Subash ·

ya this is a really tricky one im not getting that way

1
Akand ·

wel....try these ill giv more...............wel prateek this wasa pre board 3 q paper.......but we dint hav any preboard 3 so sir just gave it to us..

11
Mani Pal Singh ·

i have a method but a lenghty one so find a new 1
1+cosx=2cos2x/2

=0∩/2∫xsec2x/2+tanx/2

i hope iske aage koi bhi kar sakta hai!!!!!!!!!!!!
(use product rule for 1)

1
KR ·

by splitting we can get the right part but left part thinking.......

1
Akand ·

manipal............u wer on d edge gettin a lot easier method......but missed

Your Answer

Close [X]