ne1
anyother idea
DOES ANYONE HOW 2 DRAW
GRAPH
4 PARAMETRIC EQUATIONS??????????????
PLZ HLP...
tanT=Y/X+a
find cosT and then substitute in eqn 1 u will get Y in terms of X only and draw the graph.
see the eq u gave cannot be brought in terms of x-y just like that.
plot x-t and y-t and then by observing the two graphs plot x-y
that is, take some t and then find the corresponding approximate values of x and y from the graphs and then plot them on the x-y graph
the graph will be very crude but its the only way i can see....
bhaiya
at post #3
how 2 solve d equation
i am not able 2 solve tats y i asked
There is one more method I think
that is like this
take a value of the parameter.. find x and y correspondingly
then plot that point
of course this does not help a lot but see that thsi sometimes is a good way
also based on t find the range of x and y that gives you the idea of where the graph will lie in!
x=F(T)
y=G(T)
eliminate T in the two eqn. and then draw the graph using calculus.
for example
x=at2
y=2at
t=y/2a;
4ax=y2;
which is a parabola u know.
try to eliminate 't' &find an equation based on x & y only......dont tell me to do the calculation...... or else.......
how about......................eliminate t....find an eqn only in x and y.........
u cannot plot it without plotter
or do like this
plot separate X-T and Y-T graph
then in the X-Y graph, plot the points for every t