21hit by plane1 =A=0.3
not hit by plane 1 =A'=0.7
hit by plane 2=B=0.2
not hit by plane 2=B'=0.8
hit by d 2nd one is...A'B+(A')2B'.B+(A')3(B')2B.....
=(0.7)(0.2)(1+(0.7)(0.8).......)
=(0.14)(1/1-0.56)
=0.14/0.44
=7/22
=0.32
two planes 1 and 2 hit a plane in succession . the probability of 1 and2 scoring hit correctly is 0.3 and 0.2 respectively. The second plane will bomb only if 1misses it. probability the target is hited by 2nd one
ans-0.32
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