the given inequality is always true except when (x+2)/(x-2) = 0 (as lxl ≥ 0)
i.e. when x=-2
So solution is x = R-{-2}
Solution of inequality \left| \frac{x+2}{x-2}\right|>0 is
the given inequality is always true except when (x+2)/(x-2) = 0 (as lxl ≥ 0)
i.e. when x=-2
So solution is x = R-{-2}