basic qn on structure.

Whats the more stable configuration according to you?
Also an electron always form a pair in an orbital if they there is another electron available.

y it shud form a pair.if it exists in pairs kq²/r² r is so small, so huge force.so i think there must be some other reason,wat is gong to be changed incase of its spin.

can u explain breifly.

opposite spins....so opposite electric fields.....hence they cancel out....
net electric field=0.....

well i am speaking abt electrostatic force.

in ur structure...there are 3 90° bonds between l.p and b.p.
which results in unstable structure....as far as i know.....

@msp. Dude. Your structure is unstable according to me coz your structure has each electron pair has to face more repulsion from 3 bond pairs which are at right angles to it. U have placed lone pairs away but 3 lp bp repulsion is more than that. It increases the energy of the system and hence makes it unstable.

just like we will do in finding the structure which contributes in the resonance hybrid.

Just find the number of repulsions to arrive at the right structure

lone pair=LP
bond pair=BP

the order is LP-LP>LP-BP>BP-BP

ya,eure is right.this is the right way of judging the relative stability of structures.

the order LP-LP>LP-BP>BP-BP is considered effective only when any of these pair is at 90⁰ wid each other.repul;sion is considered negligible when angle is 120⁰ or 180⁰. also, neglect the BP-BP repulsion as its too weak compared to the other two.

in the first structure : there are four 90⁰ repulsions between lonepair and bonded pair and no lonepair-lonepair repulsion.

in the 2nd structure there are six 90⁰ repulsions b/w bonded pair and lone pair but no lonepair-lonepair repulsion.

thus, 1st structure is more stable then the 2nd one.