1pappu pass ho gaya lolzzzzzzzzz..........[1]
Give structure of H4P2O5.
How to distinguish between Aniline and N-methylaniline?
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23 Answers
1bajte bajte band hamari chemistry paper mein bhi baj gayi[2][2][2][2].............CHOR BAZARIII EFFECT!!!!!!
1wat is the answer to that Cr2+ is stronger reducing agent than Fe2+ ??
was the answer to the activation energy 55.something (I dont remeber whether KJ/mol or J/mol)
39english will be testing...papers are usually lengthy even though they're straightforward.
1Thanks 4 d answers,quite a few of my doubts turned out right[1]
but still in our region set 2 was the toughest it seems,others say they had a fantastic exam.
good but not a great test 4 me..
good luck for english everyone.it seems a big hurdle!
39Well...I didn't think much of iodoform that time...but what I wrote was-:
Take both compounds in separate flasks. Oxidise to acid. Decarboxylate. One will give methane gas and the other will not. LOL
govind...I thought methyl ketones and ethanol, along with some exceptions, give iodoform?
29@Pritish
Maybe Iodoform can help here...i wrote iodoform test...
wat abt u??
39Best way is GR..lol. Why would you use any other way :P
I got a pair of compounds to be distinguished...
Ethanal and Propanal..any way how to do it?
I used a wacky method which is correct but not many would think of it :P
13Yes....do saal karte karte log book dekhna is now comfortable,,,earlier i cudn't manage seeing & then calculating with 4 digits after decimal...he!he!
We got a conversion... Propanone to 2-methyl-propan-2-ol.
I used GR, any other single step process ?
39I got CaF2 lattice question...FCC lattice aur edge length specify karne ke baad bhi itna saara bakwaas likha hua tha...8 Ca2+ ions are with 4 F- ions or something...what have I to do with that? lol
Had to calculate NA, came out 6.034 x 1023. Atleast thanks to chemistry I can do log and antilog easily now.
1also if any1 got set 2.plz post the answers to numericals like q 29.19,20.
also why is Cr2+ stronger reducing agent than Fe2+?
13Yeah, pritish rite there...jitne differences pataa the, sab likh daale :D
Activation Engy - 55.smthing (kJ)
XeF2 ---sp3d, Equatorial pe lone pair to minimise repulsion & lp-bp repulsion equivalent frm all lone pairs, hence no bending.
Did nyone get "Cu" lattice waala Qn ?Ans kya hai ?
39NCl3 waala nahi kiya tha, uska OR part tha woh kiya tha...but maybe it's because fluorine is highly electronegative or something..I forgot.
XeF2 is a linear molecule as per VSEPR theory. 2 bond pairs and 2 or 3 lone pairs, something like that.
Oxidising power of an element depends on -:
1.Electron gain enthalpy -> Should be more negative
2.Bond dissociation enthalpy -> Should be less.
3.Hydration enthalpy -> Should be more.
Fluorine's EGE is less negative than chlorine's because of its compact size and electron-electron repulsions in 2p subshell. BUT
It's bond dissociation enthalpy is much lesser than chlorine's and it's hydration enthalpy is much more than chlorine's. Hence it is a stronger oxidising agent.
1NCl3 is an endothermic compound whereas NF3 is exothermic compound
XeF2 is a linear molecule without a bend
EA of Cl>F but still F is better oxidising agent.
1well thats ineresting...didnt know they varied from region to region.
posting few doubts on p block pritish,plz try and answer them
1okay got the structure of H2P2O5 right.
no need to answer it.
but plz give answers to numerical ques!
39Ahh I didn't have those questions...I had boiling point elevation, FCC lattice and Kohlrausch's Law
1lol!certainly not,i think.
cud u give the answers to numerical ques like freezing pt depression,activation energy.
39Mine was set 2...same as yours but probably a bit different because of different cities?
1thanks pritish,wrote azo dye though wasnt confident about Fe Cr doubt.
which set did u get?
39Editing : You can explain it on basis of electrode potentials of Fe2+ and Cr2+. Oxidation potential of ferrous ion will be more than cupric ion as it can lose an electron easily to obtain stable d5 config.
You can distinguish aniline and N-methyl aniline by azo dye test, or diazo coupling. Couple each with phenol....or you can even use Hinsberg's Test.
What were the numericals? Can you post them?