4
UTTARA
·2010-01-17 09:19:26
2) Which of the following carbocations are formed during the formation of given products.
CH3----CH CH----CHCH2 --HCL---->
CH3--CH2---CHCH--CH2---cL + CH3---CH(cL)----CHCH----CH3
(A) CH3---CH2----CH+---CHCH2
(B) CH3 --- CH2--CHCH---CH2+
(C) CH3---CHCH---CH+---CH3
(D) CH3----CHCH---CH2---CH3+
4
UTTARA
·2010-01-17 09:25:23
Compound (x) C3H6O decolourises Br water , with dil H2So4it undergoes hydrolysis to give (y) and (z). The correct statements are :
(A) (x) is an ether (b) (X) is an alkene
(C) (X) is cyclic compound (d) Both y and z are carbonyl compounds
4
UTTARA
·2010-01-17 10:06:33
ALL THE ABV R MULTI ANS TYPE
11
Tush Watts
·2010-01-17 10:20:32
Ans 1) b, c (NOT SURE) ????????
13
Avik
·2010-01-17 10:57:30
1)Electrochem. no idea
2)AC
3)AB
4
UTTARA
·2010-01-17 17:51:35
ANS GIVEN
1) A B D
( But I got B D)
2) A B C
( I want the mechanism)
3) a b
(But how??? I want explanation)
13
Avik
·2010-01-17 22:47:40
3) Hydrolysis gives 2 products, matlab it is an ether, tht too non-cyclic.
As, there is 1 degree unsturation, & it is declourising Br2 water, a double bond is present.
So, X will be.... CH2=CH-O-CH3.
Y & Z are- CH3-CHO & CH3-OH.
Hence, only A & B are rite.....