33I have also read the same... and whoever i have asked has replied the same...
But i think CCl3H>CCl2H2>Ch3Cl>CCl4
Arrange according to dipole moment...
CHCl3, CH2Cl2, CH3Cl
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33CCl4 was not in question :P
Can U xplain why CH2Cl2<CH3Cl
and so on....
33
1dipole moment of the hydrocarbon depends on geometry i.e.
μ is inversly proportion to θ , so it iz.
expermental value of μ r as follows:-
CHCl3 = 1.02 D ,
CH2Cl2 = 1.55D ,
CH3Cl = 1.93 D.
33That experimental values....
Ok consider CH2Cl2...
μ b/w C-Cl be x
Here two x are at angle of 110° so there vector sum > x (in CH3Cl)
i am confused...
1as i think , explanation is ,Cl is a bulky group , hence as no. of Cl increases , der will steric hindrance increases and the angle increases , and den due to its geometry, the polarity of the C - Cl bond tends to cancele.
and as i already mention'd , μ ≈ 1/θ,so as angle increases (due 2 s.h.), μ decreases..
1H -> electropositive than C
Cl -> electronegative than C
In CH3Cl, three H make C more electronegative which is pulled by Cl. So net dipole is large.
In CH2Cl2, shared bet. 2 Cl atoms..
In CHCl3, 3 Cl atoms are present, which distrubutes more and hence less compared to CH3Cl and CH2Cl2 net dipole moment.
I think this is a reason... please correct me if I am wrong..
1d thing i want 2 explain wid such a lamba-lamba explaination, u did it very simpl way.
gr8.
1priyam while calculating the ans with the help of vector analysis assuming bond angle to be 109.5 it will be CH2CL2 having the highest........ but as the chlorine atoms are increasing the free redical in hyperconjugative structure is more n more delocalised by pπ-dπ bonding ...thus making the structure more planar.......... hence dipole moment decreases