MgCl2 + 2NaHCO3 → mg(HCO3)22 + 2NaCl
Mg(HCO3)2 ------------------------> MgCO3 + H2O + CO2
heat (white precipitate)
So,.................
ans : b
A sodium salt of an unknown anion when treated with MgCl2 gives white precipitate only on boiling. This anion is..
a) SO42-
b) HCO3-
c) CO32-
d) NO3-
MgCl2 + 2NaHCO3 → mg(HCO3)22 + 2NaCl
Mg(HCO3)2 ------------------------> MgCO3 + H2O + CO2
heat (white precipitate)
So,.................
ans : b
@tina, is the reaction given by u exothermic, if not, how can it breaak up i.e. how can the later reaction follow up???