11yeah but what's the reason ???
Ques 1) A body centred cubic lattice is made up of hollow spheres of B. Spheres of Solid A are present in hollow spheres of B. Radius of A is half of radius of B. What is the ratio of the total volume of spheres of B unoccupied by A in a unit cell and volume of unit cell ?
Ques 2) Select the correct statement(s) * :-
(a) Cs C l changes to Na C l structure on heating.
(b) Na C l changes to Cs C l structure on applying pressure.
(c) Co -ordination no. dec on applying pressure
(d) Co -ordination no. inc on heating.
* For Ques 2, one / more answers is / are correct
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11 Answers
106When we heat things, they tend to expand (or molecules tend to vibrate more). So they will try to spread out. This can occur if the coordination no. decreases.
Conversely, on application of pressure, they will try to become more compact which is possible on increasing coordination no.
11Options given :-
(a) 0.04 (b) 0.094 (c) 0.09158 (d) none of these
& Answer is given as (d)
1Well solid state is really easy... I love that chapter!
In Qsn.1, first draw the structure of BCC wid spheres B. Radius of B = r, Side of cube = a.
Then, relating the length of diagonal and radius of B spheres, we get:
a = 4√33r
Total volume of A spheres is given by:
2 x 4∩ r33 8
Hence remaining volume is 2 x 4∩ 7 r33 8
(Since total volume of outer spheres - total volume of inner spheres = volume unoccupied, i.e 1 - 18 = 78 )
Dividing this by volume of cube, a3
We get:
2 x 4∩ 7 r33 8
--------------- %
(4√33r )3
Divide the two, cancel out common terms and you get answer as 0.5838642%
Just re-check my calculations and cancellations, cuz i think there might be some calculation error. Steps, otherwise, are perfect.
Hence answer according to my calculations should be None of these.
1lol....jai ho wat outstanding answer :P
0.0154647393532935472636379137634458*2
simply 0.031!!!!!!!!!ha!!!!!ha!!!!!!!!
1Ankur can u xplain why have u multiplied the term wid 2 durin 'remaining volume calculation'?????
The spheres with radius A are within the one with radius B....the number of sphere wid radius B is 1.....other wise if there would 2 spheres wid radius B (one in the centre n half on each side) then the total nos of sheres with radius A would have been 4...
Correct me if i am wrong...
1Hey Avishek, let me give u a simple picture of what is my thought on this.
I considered one sphere of radius B, from which i remove the volume of sphere A, ok? So i get the volume of the remaining portion of the sphere of radius B.
Since the qsn says its a BCC lattice, there are two spheres of radius B in the unit cell.
Since there are two such spheres, so we have to subtract the volume of sphere A from each of these 2 spheres. Hence i took 2 common from the 'remaining volume calculation'
nd if u wanna know why,
its cuz, writing 1 - 18 is better than writing 2 - 216 aint it?
hope u got my point right... i guess my explanation must have been a bit confusing for ya.... in tht case srry fr the inconvenience [6]
1yes i get it but i think there is som calculation mistake for which i was havng a prob LET ME EXPLAIN IT WID SOLUTION
a=(4/√3)r
volume of sphere wid radius B = 4 ∩ r33
now A = 12 B
therefore, there are two spheres wid radius a in a single one wid B
volume of a sphere wid radius A = 4 ∩ (r2)33
which is equal to 4 ∩ r33 . 8
now if we tak 1 sphere of radiud B it has 2 wid A
so, total volume of A's = 2 4 ∩ r3 3 . 8
now the remaining volume of the one wid B = 4 ∩ r3 3 - 2 4 ∩ r3 3 . 8
= 4 6 ∩ r3 3 . 8
now u can devide it wid 2 as there are 2 sphere wid radius B in a bcc structure.....
and the option is ofcourse 'd'
and the answer becomes ' .255 '