1shud i pink myself??????
naa its too easy...
i think yaa....atleast i solved it........hehe
The number of electrons present in 63 mg of HNO3 is 1.92 x 1022
Please explain how
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5 Answers
11 mole=63 grams
and in one molecule of HNO3 ther are 32 electrons
so in 63 mg.....there are 32x6.022x1023x10-3
=1.92x1022......
hehe
11hehe.....u r a starter tormented....thts y u think its beautiful.......
its easy actually..................
ull laugh at these questions when u r fully prepared for the JEE.........
but alas, these days JEE is givin these kind of questions only...
hehe
1HNO3 has mol. wt. =63
so its 1 mole weighs 63 gm
and tere r 32 e- in one molecule of HNO3
so in 63 mg.tere r 32x6.022x1023 x10-3
=1.92x1022
tats it