481Mass of liquid intially=Mass of liquid finally
h*A*p=h'*A*p'
from here we are getting p'=h*p/h'
Ab phir se h' ka term aa jaa rha hai :P
My approach...
Initially height is h and let after the temp. is increased to 100°C the height be h'.
The buoyant force(U)=h*A*p*g(Initially,and A is the area of cross section of the cylinder)
After the temp. increased to 100°C, U'=h'*A*p'*g(where p' is the density of the liquid after increasing the temp.)
B=U'*V'/A*del.V
del.V=V'*y*del.T
Putting value of del.V in above eq. we get...
B=h'*p'*g/y*del.T
h'=B*y*del.T/h'*p'*g
Now putting h' in velocity of efflux eq.,we get
v=√2B*y*del.T/p'
Ab failasy ho rha hai iss "p'" mein how would i evaluate dat????
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