ok whatever i hv understood ,
w=2Ï€f
ans i) i hv given the expression as at time t
C12V02cos2wt/(2πa2ε0)
time average of sin2θ=1-time avg.cos2θ=1/2
hence final expression =
C12V02/(4πa2ε0)
ans ii)
μ0C22V02w2b/2h
iii)speed of light expression =
(C2wa/C1)*√(2πb/h)
iv) just put and calculate!