another olympiad question

3 Answers

1
Rohan Ghosh ·

i am not able to understand the figure clearly

1
Rohan Ghosh ·

ok whatever i hv understood ,
w=2Ï€f

ans i) i hv given the expression as at time t

C12V02cos2wt/(2πa2ε0)

time average of sin2θ=1-time avg.cos2θ=1/2

hence final expression =
C12V02/(4πa2ε0)

ans ii)

μ0C22V02w2b/2h

iii)speed of light expression =

(C2wa/C1)*√(2πb/h)

iv) just put and calculate!

9
Celestine preetham ·

well done thats right

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