BITSAT 10 ,,,,,,,,,,,,,,

Its true. Li+ ion is small, so it is highly hydrated. Thus its hydrated ion size is largest. You can refer to JD Lee.

Q)^....at X--->Y + Z
a b c
a-x b+x c+x...................now put the givn values and get a+b=6....and get
a=6

@Phelps : yup

Ans is 6

Can u post ur solution

(^) ans seems a)6 to me...

@smsm : Ans given is pz (which i think is wrong)

Even I'm not sure of the correct ans

Sum of the series 1/(4.5.6)+1/(5.6.7)+1/(6.7.8)+...upto ∞ is
logee/20
logee/10
logee/40
none of these

the hydration of lithium is the most as the hydrating power is inversely proportional to the size of the ion. so after hydration hydration radius of lithium is the most. so the answer is TRUE.

And thanks u r rite abt that Hydration qs

@Sridhar ans for % qs is PbO

(^) Concentrations of X , Y , Z r 4 , 2 , 2.8 mol/l respectively. Then iinitial concentration of X is

X < ------ > Y + Z

(A) 6

(B) 8

(C) 10

(D) 4

Ans for (*) qs is given is Faraday but that can not be true as moth r dimensionally diff units

So I too go with D

However any one has views against D can cum up

u mean Li +2 , Na + 2 n so on ....

but qs says Li + Na + so on .....:(

add + 2 each element.......dats wat gvn in op agarwal....editing

but in that hydrated ions qs ions r given

in op agarwal as u said elements r given

ans for (*) qs is 1 faraday

but in op agarwal it is gvn ---Li+>Cs+>Rb+>K+>Na+

RADIOACTIVE ONE.....i think its either c or d...
it cant b (a)......1 curie=3.7 x 10¹⁰ dps---so it cant b (b)
as far as i remember, 1 becquerel = 1 dps....but not gvn in d ans..so m8 b D

RADIUS OF HYDRATED ION----FALSE...

(*) A radioactive element undergoes 1 dps then it is called

(A) 1 Faraday

(B) 1 Curie

(C) 1 Rutherford

(D) None

Ans given A but I go with D