1.
(666666...)2+(888888........)2
=36(10n-1)281+64(10n-1)281
=100(10n-1)281
1 )(6.6.6.6....6)2+(8.8.8.8.8......8)2=
where each of the number contain n digits ?
2 ) the sequence 1,2,2,4,4,4,4,8,8,8,8,8,8,8,8........where n consecutive terms have the value n then 1025th term is
?
plz kindly post detailed solution ?
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2 Answers
Aditya Bhutra
·2011-12-12 04:28:32
2) note that from 2nth term to (2n+1-1)th term the number is 2n
now 210<1025 < 211-1 hence the term will be 210=1024
souradipta Sen
·2012-04-20 11:37:37