General Physics

466

Himanshu Giria ·2014-02-07 16:56:43

it is given :

r2-r1v2-v1=|r2-r1||v2-v1|
pl explain how to get the rhs part ...

2305

Shaswata Roy ·2014-02-08 01:59:08

Let's assume that the particles collide after time t.

Position of particle 1 at that time is,

r₁+v₁t

And that of 2 is,

r₂+v₂t

Since they collide the position of the 2 particles at the time of collision must be the same.

r₂+v₂t = r₁+v₁t
â†’r₂-r₁ = -t (v₂-v₁)

Now take modulo on both the sides,

â†’|r₂-r₁| = -t |v₂-v₁|

Eliminate t to get the required result.

UP 1 DOWN 2
Himanshu Giria when we are taking modulus on R.H.S why does'nt -t come into the modulus and become t(positive)
Upvote·0· Reply ·2014-02-08 02:59:49
Shaswata Roy It will become positive.Sorry for that mistake.
Upvote·0· Reply ·2014-02-08 07:54:33
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466

Himanshu Giria ·2014-02-06 22:51:38

somone plz try out this one ...

1161

Akash Anand ·2014-02-07 05:45:15

Whether the answer is in the form of r2-r1v1-v2=const. Constant can take any positive value.

466

Himanshu Giria ·2014-02-07 09:00:01

Yes sir .. i 2 thot that but it is given =|r2-r1v2-v1|

UP 0 DOWN 1
Anurag Ghosh Modulus is given because in the given vectors you don't know which is greater in magnitude.
Upvote·0· Reply ·2014-02-07 16:10:16
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466

Himanshu Giria ·2014-02-11 04:32:43

then we are getting r₂-r₁v₂-v₁ = -|r₂-r₁||v₂-v₁|
but the ans is r₂-r₁v₂-v₁ = |r₂-r₁||v₂-v₁|

Coll.