466it is given :
r2-r1v2-v1=|r2-r1||v2-v1|
pl explain how to get the rhs part ...
Two particles ,1 and 2, move with constant velocities v1 and v2 .
At the initial moment their radius vectors are r1 and r2 .
How must these four vectors be interrelated for the particles to collide ?
-
UP 0 DOWN 0 0 6
6 Answers
466
2305Let's assume that the particles collide after time t.
Position of particle 1 at that time is,
r1+v1t
And that of 2 is,
r2+v2t
Since they collide the position of the 2 particles at the time of collision must be the same.
r2+v2t = r1+v1t
→r2-r1 = -t (v2-v1)
Now take modulo on both the sides,
→|r2-r1| = -t |v2-v1|
Eliminate t to get the required result.
- Himanshu Giria when we are taking modulus on R.H.S why does'nt -t come into the modulus and become t(positive)Upvote·0· Reply ·2014-02-08 02:59:49
- Shaswata Roy It will become positive.Sorry for that mistake.
1161Whether the answer is in the form of r2-r1v1-v2=const. Constant can take any positive value.
466Yes sir .. i 2 thot that but it is given =|r2-r1v2-v1|
- Anurag Ghosh Modulus is given because in the given vectors you don't know which is greater in magnitude.
466then we are getting r2-r1v2-v1 = -|r2-r1||v2-v1|
but the ans is r2-r1v2-v1 = |r2-r1||v2-v1|