1
Rohan Ghosh
·2008-12-11 20:15:18
let the mass of the stones be m and the mass of the boat be M
initially ,
let the water displaced by the system =V
then pVg=(M+m)g
V=M/Ï + m/Ï
finally let the water displaced be V'
V'= water displaced by M(V1) water displaced by m(V2)
then
pV1g=Mg
V1=M/Ï
let density of stones=Ïs
as Ïs>p
the stones will be immersed
volume displaced= volume of stones = m/ps
hence V' = M/Ï + m/(Ïs)
V'-V=m(1/ps-1/p)
as ps>p
V'<V
hence as water displaced is less
water level will decrease
1
dimensions (dimentime)
·2008-12-11 21:01:38
i think level of water remain's the same.......................no change....
1
Rohan Ghosh
·2008-12-11 21:03:29
no dimensions , check my method ..
39
Dr.House
·2008-12-11 21:09:49
rohan actually we discussed the same questions in the class a few days before.
what u have said is correct but it need not be the case always. check once again.. u are makng some assumptions while getting to the answer.
1
?
·2008-12-11 22:57:50
ok so rohan u mean to say that water levek will rise ?
62
Lokesh Verma
·2008-12-11 23:25:35
The answer is that water level will decrease.
The assumption is that the stone has very high density.! (I dont think we need any other assumption)
1
Akand
·2008-12-12 02:11:32
guyzzz. this is a very standard ques............ d water level will decrease even if our logic says no.....physics does so........
1
?
·2008-12-17 12:10:50
and for the sake of being practical we can think of the level of the water being decreased with respect to the boat as the stones are unloaded !!