function....

66. Let f : (â€“1, 1) â†’ R be a differentiable function with
f(0) = â€“1 and fâ€²(0) = 1. Let g(x) = [f(2f(x) + 2)]². Then
gâ€²(0) =

(1) 4 (2) â€“4
(3) 0 (4) â€“2

3 Answers

g' ( x ) = 2 f ( 2f( x ) + 2 ) f ' ( 2f( x ) + 2 ) 2f ' (x)

g'(0) = 2 f ( 0 )f ' (0 ) 2f' (0)
= 2 . -1 . 1 . 2 . 1 = - 4

this func is y=x-1

now put values and answer is -4

ans is -4

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