1Cud sum1 tell me if this is the correct answer?
The period revolution of a nearest satellite around a planet of radius R is T. Period of revolution around another planet, whose radius is 3R but having same density is :
also give appropriate reason
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4 Answers
62gMm/r2=mw2r
gM=w2r3
So having a particular w, nothing can be said because the r of the rotational orbit is different from R of the planet.
So i dont see how this can be solved... (Am i sleeping or something else is wrong?)
1Time period of a satellite near a planet is given as:
T=√(4*pi2*r3/GM)
=√(4*pi2*r3/G*(density)*4/3*pi*r3)
=√(3*pi/G*density)
Which shows that if density is const., time period is independent of radius. Hence answer is T.
