24how did u get """LC = 0.1mm"""????
The side of a cube is measured by vernier callipers. (10 divisions of a vernier scale coincide with 9 divisions on main scale where 1 division on main scale is 1 mm.)
The main scale reads 10 mm. first division of the vernier scale coincides with the main scale.
mass of cube is 2.736 g.
Find the density of cube in appropriate significant figures.
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9 Answers
106LC = 0.1mm
Side of cube = 10+1*0.1 = 10.1mm = 1.01 cm
volume of cube = 1.03 cm3
So, density = 2.736/1.03 = 2.66 gm/cm3
1reading is 10.1 mm = 1.01 cm
Volume = (1.01)3 = 1.03 cm3 (the answer should have same no. of sig. fig as each individual units ).
Density = 2.736 g/1.03 cm3 = 2.6563 g / cm3
Density = 2.66 g / cm3 (roundoff to 2 sig fig .. because the no. of sig fig is same as in the no. having the smallest no . of sig fig)
1061 MSD = 1mm
9 MSD = 9mm
10 VSD = 9mm
1 VSD = 0.9mm
LC = 1 MSD - 1 VSD = 0.1 mm