look
here
u=0
a=g
and s= 5m
using s=ut + 1/2 a t^2
find t = 1.01
find final velocity v = 9.89 m/s
then for motion in sand
using
v^2 = U^2 + 2as
find a = - 490m/s^2
a ball is dropped from a height of 5m onto a sandy floof and penentrates the sand upto 10 cm before coming to rest . find the retardation of the ball in sand assuming it to be uniform.
Using equations of motion, first find the final velocity of the ball just as it hits the sandy floor(u = 0, a = g, s = 5, v = ?). From thereon, use another equation of motion to find retardation (u = v found in previous, s = 0.1m, v = 0, a = ?).
look
here
u=0
a=g
and s= 5m
using s=ut + 1/2 a t^2
find t = 1.01
find final velocity v = 9.89 m/s
then for motion in sand
using
v^2 = U^2 + 2as
find a = - 490m/s^2
what gravity had taken 5 m to make, the sand destroys in 10 cm....
applying v2=2gS1=2aS2 we easily get the result in 1 step.. [:D]
we know g, S1 and S2 and thus, easily can calculate a!!
a= gS1S2=g50.1=50g=490.5 m/s2 [1][1]