kya title doon???????

@tapan he asked 4 title & not the answer[9]

hey, plz give complete solution..........not juzz the ption...........

ans is (a)

hey, ans is also given..........plz give the complete steps.........

hey yaar u can easily eliminate options b and c...because the C.O.M. of the system will be towards AB rod only...about others thinking....

explanation???

mani u deserv a pink 4 dat!!!

In accordance with sky's diagram...Let the centre of mass of rod AB be considered at origin....and that of MC be at a distance of L from origin...
Therefore...

x=(M(0)+2M(L))/3M

=2L/3....

where, x= distance of center of mass of the system from M taking M as origin....

Thus MP=2L/3...
Therefore CP=4L/3....

i think it would be clear now....

this site is meant for this only...if a person starts saying thank u na..then his post will mount up to many...
don't say thanks to me...

otherwise...ur welcome....