PHY.>>.INTEGER >TYPE

Ans 2)6 kg
we find that when both ice and water are at 0°C still the water can supply 80000 cal of heat enough to melt 1000g(1kg) of ice to water.
so total amt of water finally at 0°C is (5+1)kg=6 kg

α=3 acc. to me

2 capacitors in parallel and one in series, u have to find v across the parallel one.

6

20000 cal from -20 to 0 ice
100000 cal from 20 to 0 water
80000 cal left
enough to melt 1 kg ice to water
so
1kg ice 6kg water

Q1...TAPAS...U RE RONG
Q2...6 IS DA ANS MANY OF US R GETTIN...BUT ANS GIVN 2

Potential of the 1st plate and the last plates are 0.

Now total charge on 3rd plate is 0. Let the charge on 4th plate and 1st plates be q' and q".

P.D of 1=0 implies q'=q3.

Similarly P.D of 4th plate is 0, so q" is found out....

Now see V₁-V₄=(V₁-v₂)+(V₂-V₃)+(V₃-V₄)=0....since both V₁=V₂=0.

Since net charge on V₃=0, we can get the middle term i.e. V₂-V₃.
Pls correct me if wrong.