please verify doubts......

a point mass m starts from rest and slides down the surface of a frictionlesssolid sphere of radius r as shown in fig.(a)measur angles from the vertical and P.E.from the top(b)change in P.E.of the mass with the angle(c)K.E. as a function of angle(d)angle at wich it leaves contact(e)if there is friction wwat will happen??

13 Answers

6
Kalyan IIT-K Beware I'm coming ·

ans.
(a)angle fromvertical is θ=30.??
(d)the angle at wich it loses contact is tanθ=2??

are the radial acc.=gcosθ
and tangentialacc.=gsinθ??

pls verify...

1
sanchit ·

have a doubt................in first part we have to find the angle travelled while the mass loose contact na(widout friction)..........

1
sanchit ·

if m getting the question right...then the answer to first part m getting is====cos inverse 3/4

1
sanchit ·

velocity at theta angle m getting is ......vtheta2=gR{(9/4)-2cos(theta)}

1
sanchit ·

just put the theta nd nd u will gett the vel. and K.E..................if m right

6
Kalyan IIT-K Beware I'm coming ·

yes sanchit ur ri8..and i got the ans as 30

6
Kalyan IIT-K Beware I'm coming ·

no one trying?????

6
Kalyan IIT-K Beware I'm coming ·

koi toh help karo yarr....

6
Kalyan IIT-K Beware I'm coming ·

are the radial acc.=gcosθ
and tangentialacc.=gsinθ??

1
sanchit ·

1
sanchit ·

srry for the bad handwritinggg..........hehehe[1][1][1][1]

6
Kalyan IIT-K Beware I'm coming ·

pls somebody check the ans given by me......n help me in the frictional part.

6
Kalyan IIT-K Beware I'm coming ·

in the frictional part the block will not leave the contact where is sud hav done if friction was'nt there.it will leave contact somewhere after that paricular point????

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