wen the range of projectile on a n inclined plane is maximum then
a)focus of the path is on the plane
b)focus of the path is below the plane
c)focus of path is above the plane
d)focus of path can be at any place
9abv plane
it is so for horizontal plane which is an xtreme case of inclined plane
( focii = (u2sin2θ/2g , u2sin2θ/2g)
if pt of throw is (0,0)
can be derived frm eq of projectile)
hence focii always abv pt of release and in this case slope is downwards(range max) so its obvious focii abv plane also)
1the ans id (d) as it acts as a parabola .Let the centre of the throw be the origin therefore as its angle changes its focus can be at any place
